Integrand size = 33, antiderivative size = 381 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right ) \text {arctanh}(\sin (c+d x))}{4 d}+\frac {\left (2 a^6 C+8 b^6 (7 A+6 C)+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)\right ) \tan (c+d x)}{105 b^2 d}+\frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x) \tan (c+d x)}{420 b d}+\frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d} \]
[Out]
Time = 1.12 (sec) , antiderivative size = 381, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.242, Rules used = {4178, 4167, 4087, 4082, 3872, 3855, 3852, 8} \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a b \left (a^2 (8 A+6 C)+b^2 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))}{4 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) \tan (c+d x) (a+b \sec (c+d x))^4}{105 b^2 d}+\frac {a \left (2 a^2 C+42 A b^2+31 b^2 C\right ) \tan (c+d x) (a+b \sec (c+d x))^3}{210 b^2 d}+\frac {\left (2 a^4 C+3 a^2 b^2 (14 A+9 C)+8 b^4 (7 A+6 C)\right ) \tan (c+d x) (a+b \sec (c+d x))^2}{210 b^2 d}+\frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \tan (c+d x) \sec (c+d x)}{420 b d}+\frac {\left (2 a^6 C+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)+8 b^6 (7 A+6 C)\right ) \tan (c+d x)}{105 b^2 d}-\frac {a C \tan (c+d x) (a+b \sec (c+d x))^5}{21 b^2 d}+\frac {C \tan (c+d x) \sec (c+d x) (a+b \sec (c+d x))^5}{7 b d} \]
[In]
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Rule 8
Rule 3852
Rule 3855
Rule 3872
Rule 4082
Rule 4087
Rule 4167
Rule 4178
Rubi steps \begin{align*} \text {integral}& = \frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^4 \left (a C+b (7 A+6 C) \sec (c+d x)-2 a C \sec ^2(c+d x)\right ) \, dx}{7 b} \\ & = -\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^4 \left (-4 a b C+2 \left (a^2 C+3 b^2 (7 A+6 C)\right ) \sec (c+d x)\right ) \, dx}{42 b^2} \\ & = \frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^3 \left (12 b \left (14 A b^2-a^2 C+12 b^2 C\right )+4 a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) \sec (c+d x)\right ) \, dx}{210 b^2} \\ & = \frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^2 \left (12 a b \left (98 A b^2-2 a^2 C+79 b^2 C\right )+12 \left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) \sec (c+d x)\right ) \, dx}{840 b^2} \\ & = \frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x)) \left (-12 b \left (2 a^4 C-16 b^4 (7 A+6 C)-3 a^2 b^2 (126 A+97 C)\right )+12 a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x)\right ) \, dx}{2520 b^2} \\ & = \frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x) \tan (c+d x)}{420 b d}+\frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {\int \sec (c+d x) \left (1260 a b^3 \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right )+48 \left (2 a^6 C+8 b^6 (7 A+6 C)+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)\right ) \sec (c+d x)\right ) \, dx}{5040 b^2} \\ & = \frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x) \tan (c+d x)}{420 b d}+\frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}+\frac {1}{4} \left (a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right )\right ) \int \sec (c+d x) \, dx+\frac {\left (2 a^6 C+8 b^6 (7 A+6 C)+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)\right ) \int \sec ^2(c+d x) \, dx}{105 b^2} \\ & = \frac {a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right ) \text {arctanh}(\sin (c+d x))}{4 d}+\frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x) \tan (c+d x)}{420 b d}+\frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d}-\frac {\left (2 a^6 C+8 b^6 (7 A+6 C)+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{105 b^2 d} \\ & = \frac {a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right ) \text {arctanh}(\sin (c+d x))}{4 d}+\frac {\left (2 a^6 C+8 b^6 (7 A+6 C)+a^4 b^2 (42 A+23 C)+8 a^2 b^4 (49 A+39 C)\right ) \tan (c+d x)}{105 b^2 d}+\frac {a \left (4 a^4 C+12 a^2 b^2 (7 A+4 C)+b^4 (406 A+333 C)\right ) \sec (c+d x) \tan (c+d x)}{420 b d}+\frac {\left (2 a^4 C+8 b^4 (7 A+6 C)+3 a^2 b^2 (14 A+9 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{210 b^2 d}+\frac {a \left (42 A b^2+2 a^2 C+31 b^2 C\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{210 b^2 d}+\frac {\left (a^2 C+3 b^2 (7 A+6 C)\right ) (a+b \sec (c+d x))^4 \tan (c+d x)}{105 b^2 d}-\frac {a C (a+b \sec (c+d x))^5 \tan (c+d x)}{21 b^2 d}+\frac {C \sec (c+d x) (a+b \sec (c+d x))^5 \tan (c+d x)}{7 b d} \\ \end{align*}
Time = 6.62 (sec) , antiderivative size = 234, normalized size of antiderivative = 0.61 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {105 a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right ) \text {arctanh}(\sin (c+d x))+\tan (c+d x) \left (420 \left (a^4+6 a^2 b^2+b^4\right ) (A+C)+105 a b \left (b^2 (6 A+5 C)+a^2 (8 A+6 C)\right ) \sec (c+d x)+70 a b \left (6 A b^2+6 a^2 C+5 b^2 C\right ) \sec ^3(c+d x)+280 a b^3 C \sec ^5(c+d x)+140 \left (a^4 C+6 a^2 b^2 (A+2 C)+b^4 (2 A+3 C)\right ) \tan ^2(c+d x)+84 b^2 \left (A b^2+3 \left (2 a^2+b^2\right ) C\right ) \tan ^4(c+d x)+60 b^4 C \tan ^6(c+d x)\right )}{420 d} \]
[In]
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Time = 1.68 (sec) , antiderivative size = 317, normalized size of antiderivative = 0.83
method | result | size |
parts | \(-\frac {\left (A \,b^{4}+6 C \,a^{2} b^{2}\right ) \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (4 a A \,b^{3}+4 a^{3} b C \right ) \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}-\frac {\left (6 A \,a^{2} b^{2}+a^{4} C \right ) \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}-\frac {C \,b^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )}{d}+\frac {a^{4} A \tan \left (d x +c \right )}{d}+\frac {4 A \,a^{3} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {4 C a \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\) | \(317\) |
derivativedivides | \(\frac {a^{4} A \tan \left (d x +c \right )-a^{4} C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+4 A \,a^{3} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 a^{3} b C \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-6 A \,a^{2} b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-6 C \,a^{2} b^{2} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+4 a A \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+4 C a \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )-A \,b^{4} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )-C \,b^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(384\) |
default | \(\frac {a^{4} A \tan \left (d x +c \right )-a^{4} C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+4 A \,a^{3} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 a^{3} b C \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-6 A \,a^{2} b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-6 C \,a^{2} b^{2} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+4 a A \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+4 C a \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )-A \,b^{4} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )-C \,b^{4} \left (-\frac {16}{35}-\frac {\sec \left (d x +c \right )^{6}}{7}-\frac {6 \sec \left (d x +c \right )^{4}}{35}-\frac {8 \sec \left (d x +c \right )^{2}}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(384\) |
parallelrisch | \(\frac {-5880 a b \left (a^{2} \left (A +\frac {3 C}{4}\right )+\frac {3 \left (A +\frac {5 C}{6}\right ) b^{2}}{4}\right ) \left (\frac {\cos \left (7 d x +7 c \right )}{7}+\cos \left (5 d x +5 c \right )+3 \cos \left (3 d x +3 c \right )+5 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+5880 a b \left (a^{2} \left (A +\frac {3 C}{4}\right )+\frac {3 \left (A +\frac {5 C}{6}\right ) b^{2}}{4}\right ) \left (\frac {\cos \left (7 d x +7 c \right )}{7}+\cos \left (5 d x +5 c \right )+3 \cos \left (3 d x +3 c \right )+5 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (\left (3780 A +4200 C \right ) a^{4}+25200 \left (A +\frac {28 C}{25}\right ) b^{2} a^{2}+4704 b^{4} \left (A +\frac {6 C}{7}\right )\right ) \sin \left (3 d x +3 c \right )+\left (\left (2100 A +1960 C \right ) a^{4}+11760 b^{2} \left (A +\frac {4 C}{5}\right ) a^{2}+1568 b^{4} \left (A +\frac {6 C}{7}\right )\right ) \sin \left (5 d x +5 c \right )+\left (\left (420 A +280 C \right ) a^{4}+1680 b^{2} \left (A +\frac {4 C}{5}\right ) a^{2}+224 b^{4} \left (A +\frac {6 C}{7}\right )\right ) \sin \left (7 d x +7 c \right )+8400 a b \left (\left (A +\frac {31 C}{20}\right ) a^{2}+\frac {31 \left (A +\frac {283 C}{186}\right ) b^{2}}{20}\right ) \sin \left (2 d x +2 c \right )+6720 a b \left (\left (A +\frac {5 C}{4}\right ) a^{2}+\frac {5 \left (A +\frac {5 C}{6}\right ) b^{2}}{4}\right ) \sin \left (4 d x +4 c \right )+1680 a b \left (a^{2} \left (A +\frac {3 C}{4}\right )+\frac {3 \left (A +\frac {5 C}{6}\right ) b^{2}}{4}\right ) \sin \left (6 d x +6 c \right )+2100 \left (\left (A +\frac {6 C}{5}\right ) a^{4}+\frac {36 b^{2} \left (A +\frac {4 C}{3}\right ) a^{2}}{5}+\frac {8 b^{4} \left (A +2 C \right )}{5}\right ) \sin \left (d x +c \right )}{2940 d \left (\frac {\cos \left (7 d x +7 c \right )}{7}+\cos \left (5 d x +5 c \right )+3 \cos \left (3 d x +3 c \right )+5 \cos \left (d x +c \right )\right )}\) | \(476\) |
norman | \(\frac {\frac {8 \left (175 a^{4} A +630 A \,a^{2} b^{2}+91 A \,b^{4}+105 a^{4} C +546 C \,a^{2} b^{2}+53 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{35 d}-\frac {\left (4 a^{4} A -8 A \,a^{3} b +24 A \,a^{2} b^{2}-10 a A \,b^{3}+4 A \,b^{4}+4 a^{4} C -10 a^{3} b C +24 C \,a^{2} b^{2}-11 C a \,b^{3}+4 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{13}}{2 d}-\frac {\left (4 a^{4} A +8 A \,a^{3} b +24 A \,a^{2} b^{2}+10 a A \,b^{3}+4 A \,b^{4}+4 a^{4} C +10 a^{3} b C +24 C \,a^{2} b^{2}+11 C a \,b^{3}+4 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 d}+\frac {2 \left (18 a^{4} A -24 A \,a^{3} b +84 A \,a^{2} b^{2}-18 a A \,b^{3}+10 A \,b^{4}+14 a^{4} C -18 a^{3} b C +60 C \,a^{2} b^{2}-7 C a \,b^{3}+6 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}}{3 d}+\frac {2 \left (18 a^{4} A +24 A \,a^{3} b +84 A \,a^{2} b^{2}+18 a A \,b^{3}+10 A \,b^{4}+14 a^{4} C +18 a^{3} b C +60 C \,a^{2} b^{2}+7 C a \,b^{3}+6 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 d}-\frac {\left (900 a^{4} A -600 A \,a^{3} b +3480 A \,a^{2} b^{2}-270 a A \,b^{3}+452 A \,b^{4}+580 a^{4} C -270 a^{3} b C +2712 C \,a^{2} b^{2}-425 C a \,b^{3}+516 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{30 d}-\frac {\left (900 a^{4} A +600 A \,a^{3} b +3480 A \,a^{2} b^{2}+270 a A \,b^{3}+452 A \,b^{4}+580 a^{4} C +270 a^{3} b C +2712 C \,a^{2} b^{2}+425 C a \,b^{3}+516 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{30 d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{7}}-\frac {a b \left (8 a^{2} A +6 A \,b^{2}+6 C \,a^{2}+5 C \,b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{4 d}+\frac {a b \left (8 a^{2} A +6 A \,b^{2}+6 C \,a^{2}+5 C \,b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{4 d}\) | \(686\) |
risch | \(\text {Expression too large to display}\) | \(1064\) |
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Time = 0.30 (sec) , antiderivative size = 325, normalized size of antiderivative = 0.85 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {105 \, {\left (2 \, {\left (4 \, A + 3 \, C\right )} a^{3} b + {\left (6 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{7} \log \left (\sin \left (d x + c\right ) + 1\right ) - 105 \, {\left (2 \, {\left (4 \, A + 3 \, C\right )} a^{3} b + {\left (6 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{7} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (4 \, {\left (35 \, {\left (3 \, A + 2 \, C\right )} a^{4} + 84 \, {\left (5 \, A + 4 \, C\right )} a^{2} b^{2} + 8 \, {\left (7 \, A + 6 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{6} + 280 \, C a b^{3} \cos \left (d x + c\right ) + 105 \, {\left (2 \, {\left (4 \, A + 3 \, C\right )} a^{3} b + {\left (6 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} + 60 \, C b^{4} + 4 \, {\left (35 \, C a^{4} + 42 \, {\left (5 \, A + 4 \, C\right )} a^{2} b^{2} + 4 \, {\left (7 \, A + 6 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{4} + 70 \, {\left (6 \, C a^{3} b + {\left (6 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{3} + 12 \, {\left (42 \, C a^{2} b^{2} + {\left (7 \, A + 6 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{840 \, d \cos \left (d x + c\right )^{7}} \]
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\[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\int \left (A + C \sec ^{2}{\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{4} \sec ^{2}{\left (c + d x \right )}\, dx \]
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Time = 0.23 (sec) , antiderivative size = 472, normalized size of antiderivative = 1.24 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {280 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a^{4} + 1680 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A a^{2} b^{2} + 336 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} C a^{2} b^{2} + 56 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} A b^{4} + 24 \, {\left (5 \, \tan \left (d x + c\right )^{7} + 21 \, \tan \left (d x + c\right )^{5} + 35 \, \tan \left (d x + c\right )^{3} + 35 \, \tan \left (d x + c\right )\right )} C b^{4} - 35 \, C a b^{3} {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{5} - 40 \, \sin \left (d x + c\right )^{3} + 33 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 210 \, C a^{3} b {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 210 \, A a b^{3} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 840 \, A a^{3} b {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 840 \, A a^{4} \tan \left (d x + c\right )}{840 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1280 vs. \(2 (366) = 732\).
Time = 0.41 (sec) , antiderivative size = 1280, normalized size of antiderivative = 3.36 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Too large to display} \]
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Time = 20.08 (sec) , antiderivative size = 755, normalized size of antiderivative = 1.98 \[ \int \sec ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a\,b\,\mathrm {atanh}\left (\frac {a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (8\,A\,a^2+6\,A\,b^2+6\,C\,a^2+5\,C\,b^2\right )}{6\,A\,a\,b^3+8\,A\,a^3\,b+5\,C\,a\,b^3+6\,C\,a^3\,b}\right )\,\left (8\,A\,a^2+6\,A\,b^2+6\,C\,a^2+5\,C\,b^2\right )}{2\,d}-\frac {\left (2\,A\,a^4+2\,A\,b^4+2\,C\,a^4+2\,C\,b^4+12\,A\,a^2\,b^2+12\,C\,a^2\,b^2-5\,A\,a\,b^3-4\,A\,a^3\,b-\frac {11\,C\,a\,b^3}{2}-5\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}+\left (12\,A\,a\,b^3-\frac {20\,A\,b^4}{3}-\frac {28\,C\,a^4}{3}-4\,C\,b^4-56\,A\,a^2\,b^2-40\,C\,a^2\,b^2-12\,A\,a^4+16\,A\,a^3\,b+\frac {14\,C\,a\,b^3}{3}+12\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+\left (30\,A\,a^4+\frac {226\,A\,b^4}{15}+\frac {58\,C\,a^4}{3}+\frac {86\,C\,b^4}{5}+116\,A\,a^2\,b^2+\frac {452\,C\,a^2\,b^2}{5}-9\,A\,a\,b^3-20\,A\,a^3\,b-\frac {85\,C\,a\,b^3}{6}-9\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (-40\,A\,a^4-\frac {104\,A\,b^4}{5}-24\,C\,a^4-\frac {424\,C\,b^4}{35}-144\,A\,a^2\,b^2-\frac {624\,C\,a^2\,b^2}{5}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (30\,A\,a^4+\frac {226\,A\,b^4}{15}+\frac {58\,C\,a^4}{3}+\frac {86\,C\,b^4}{5}+116\,A\,a^2\,b^2+\frac {452\,C\,a^2\,b^2}{5}+9\,A\,a\,b^3+20\,A\,a^3\,b+\frac {85\,C\,a\,b^3}{6}+9\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (-12\,A\,a^4-\frac {20\,A\,b^4}{3}-\frac {28\,C\,a^4}{3}-4\,C\,b^4-56\,A\,a^2\,b^2-40\,C\,a^2\,b^2-12\,A\,a\,b^3-16\,A\,a^3\,b-\frac {14\,C\,a\,b^3}{3}-12\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (2\,A\,a^4+2\,A\,b^4+2\,C\,a^4+2\,C\,b^4+12\,A\,a^2\,b^2+12\,C\,a^2\,b^2+5\,A\,a\,b^3+4\,A\,a^3\,b+\frac {11\,C\,a\,b^3}{2}+5\,C\,a^3\,b\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}-7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}-35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )} \]
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